File name without extension in bash for loop
Answer #1 100 %Use bash parameter expansion
${f%%.*}
Note that you need the greedy version because there are multiple dots in the file name.
From bash manual:
Answer #2 100 %${parameter%word}
${parameter%%word}
The word is expanded to produce a pattern just as in filename expansion. If the pattern matches a trailing portion of the expanded value of parameter, then the result of the expansion is the value of parameter with the shortest matching pattern (the ?%? case) or the longest matching pattern (the ?%%? case) deleted. If parameter is [email protected]? or ??, the pattern removal operation is applied to each positional parameter in turn, and the expansion is the resultant list. If parameter is an array variable subscripted with [email protected]? or ??, the pattern removal operation is applied to each member of the array in turn, and the expansion is the resultant list.
This should do it:
for i in *.m4a; do
ffmpeg -i $i ${i%%.*}.mp3
done